On 10/22/07, Stavros Macrakis <macrakis at alum.mit.edu> wrote:
> optimize(f(x)^f(x)) => block([%1],%1:f(x),%1^%1)
>
> which is fine, except that %1 is not interned. Why not? It is, after
> all, a bound variable.
Stavros, sorry for the late reply. It's OK by me if you want to change
optimize to intern the symbols it creates.
best,
Robert