Am 5 Nov 2007 um 12:18 hat Raymond Toy (RT/EUS) geschrieben:
>> +;; The algorithm is based on the series
> +;;
> +;; %e = sum( 1/i! ,i,0,inf )
> +;;
> +;; but sums up 1001 terms to one.
>
> Why only 1001 terms? But a glance at the actual code seems to show that
> you keep summing until H is zero, so perhaps the comment is not quite
> right. Or maybe I don't understand the comment at all.
Ray,
what I mean here is, that I sum up every 1001 summands to one summand. E.g. instead of
summing 27027 needed quotients from the Taylor series, I only use 27. Right, I sum until
the quotients are zero.
Tomorrow I answer more in detail.
Volker