-----"Richard Fateman" <fateman at cs.berkeley.edu> wrote: -----
>I assume that member -> memq is an atomic operation to return to a
>previous CVS.
More or less -- I was suggesting that Andreas go back and (I suppose
manually) change member back to memq. The arguments for doing this are
overwhelming, I think. If we need memq to be a macro for speed, that's
OK.
Barton