On Mon, Apr 14, 2008 at 2:53 PM, Neal Becker <ndbecker2 at gmail.com> wrote:
> [q1=%e^(log(10)/100)-1]
>
> How do I now get a numerical approximation to q1 (if I was using
> mathematica, which I'm used to, I'd N[%])?
ex:%$
float(ex) =0.0232...
For more digits, you can use bfloat(ex), fpprec=100.
If you want a simplified *exact* expression, you can also try radcan:
radcan(ex) => 2^(1/100)*5^(1/100)-1
-s