Simple question; log10(x) := log(x)/log(10.); 10*log10(1/(1+q1))=10*log10(1)-0.1; solve([%], [q1]); [q1=%e^(log(10)/100)-1] How do I now get a numerical approximation to q1 (if I was using mathematica, which I'm used to, I'd N[%])?