On Thu, Jun 19, 2008 at 7:27 AM, Barton Willis <willisb at unk.edu> wrote:
> By the way, Maxima can symbolically find the eigenvectors of your matrix:
I think Barton means that it can symbolically find the *characteristic
polynomial*. A more direct, but less didactic, way of finding the
characteristic polynomial is charpoly(mm,z). After that, you'll have
to find the roots/eigenvalues numerically and derive the eigenvectors
as Barton shows.
-s