-----macrakis at gmail.com wrote: -----
>On Thu, Jun 19, 2008 at 7:27 AM, Barton Willis <willisb at unk.edu> wrote:
>> By the way, Maxima can symbolically find the eigenvectors of your
>matrix:
>
>I think Barton means that it can symbolically find the *characteristic
>polynomial*.
I did express each eigenvector in symbolic form---well sort of. Each
component of each eigenvector is a sixth degree polynomial in z, where
z is any eigenvalue.
Barton