Thanks for all the help and suggestions people.
On Thu, Jun 19, 2008 at 4:05 PM, Barton Willis <willisb at unk.edu> wrote:
> -----macrakis at gmail.com wrote: -----
>
> >On Thu, Jun 19, 2008 at 7:27 AM, Barton Willis <willisb at unk.edu> wrote:
> >> By the way, Maxima can symbolically find the eigenvectors of your
> >matrix:
> >
> >I think Barton means that it can symbolically find the *characteristic
> >polynomial*.
>
> I did express each eigenvector in symbolic form---well sort of. Each
> component of each eigenvector is a sixth degree polynomial in z, where
> z is any eigenvalue.
>
> Barton
>
>