I am not sure but in the second equation it may be using the value of x=0.9
thus it may be trying to solve linsolve(0,x)...
But I am not sure...
On Fri, Sep 5, 2008 at 4:15 PM, Alexander El'bert <aee at imm.uran.ru> wrote:
> Hi,
> It is very strange for me:
> (%i1) linsolve(0.9*t-x*t,x);
> (%o2) [x=9/10]
> (%i2) keepfloat:true;
> (%i3) linsolve(0.9*t-x*t,x);
> (%o3) [x=0]
>
> Alexander mailto:aee at imm.uran.ru
>
>
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