Sorry, it seems this is not the right answer...
On Fri, Sep 5, 2008 at 4:18 PM, ahmet alper parker <aaparker at gmail.com>wrote:
> I am not sure but in the second equation it may be using the value of x=0.9
> thus it may be trying to solve linsolve(0,x)...
> But I am not sure...
>
>
> On Fri, Sep 5, 2008 at 4:15 PM, Alexander El'bert <aee at imm.uran.ru> wrote:
>
>> Hi,
>> It is very strange for me:
>> (%i1) linsolve(0.9*t-x*t,x);
>> (%o2) [x=9/10]
>> (%i2) keepfloat:true;
>> (%i3) linsolve(0.9*t-x*t,x);
>> (%o3) [x=0]
>>
>> Alexander mailto:aee at imm.uran.ru
>>
>>
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>
>