Richard Hennessy wrote:
> Try
>
> (%i5) min(-inf,minf);
> (%o5) -inf
> (%i6) max(-inf,minf);
> The sign of und is undefined -- an error.
> To debug this try debugmode(true)
>
> this seems to me that the answer %o6 should be -inf (just to be consistent with min), not an error.
Not sure, but I think the real issue is that -inf and minf are treated
as two completely separate objects. It would be nice if -inf could be
simplified to minf.
Ray