Your are right, it is not enough to check the determinant. That the
putfall of mechanically extending a solution.
Reinhard
Barton Willis schrieb:
> Maxima has a hessian function. Also, it's been a few years since I worked
> through the second derivative test for the Lagrange method, but is the
> determinant of the hessian all you need? I was thinking that you needed
> to know if the hessian is positive or negative definite. There is a
> function matrix_sign that attempts to do that.
>
> Barton
>
> -----maxima-bounces at math.utexas.edu wrote: -----
>
>
>
>> Nice Code. This is the generalization to n dimensions:
>>
>
>
>