float(sin(2^2048))?

• Subject: float(sin(2^2048))?
• From: Raymond Toy
• Date: Tue, 11 May 2010 08:43:06 -0400

What should maxima do with float(sin(2^2048))?  It currently generates
an error because 2^2048 is too big to fit in a double float.

We could do better than this by doing argument reduction of 2^2048.

Or the easy way is to tell the user to do float(bfloat(sin(2^2048))). 
Should maxima do that automatically?

Ray

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