abs & asinh

• Subject: abs & asinh
• From: Henry Baker
• Date: Tue, 22 Mar 2011 11:42:22 -0700

assume(x>0);

How come

abs(sinh(x)) => sinh(x)

but

abs(asinh(x)) => abs(asinh(x))  SHOULD BE asinh(x)

???

asinh(x) is a perfectly good 1-1/onto real increasing odd function of x.

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