integrate(1/(1-x))



why is the antiderivative of f1(x) equal to 0 at x=0,

but the antiderivative of f2(x) is undefined at x=0?

are f1(x) and f2(x) not identical functions?

f1(x):=1/(1-x);
integrate(f1(x),x);

f2(x):=-1/(x-1);
integrate(f2(x),x);