op(box(x)) --> box, but is(op(box(x)) = box) --> false.

• Subject: op(box(x)) --> box, but is(op(box(x)) = box) --> false.
• From: David R Stoutemyer
• Date: Sat, 05 Nov 2011 14:08:47 -1000

op(box(x)) --> box,  but  is(op(box(x)) = box)  --> false.
 
Also  is(op(box(x)) = 'box)  -->  false,
and   is(op(box(x)) = "box")  --> false.
 
How can I programmatically detect that op(expression) is box? 

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