Hello,
I try to solve inequalities of a list with Maxima.
A simple example is:
load(to_poly_solver) $
y : [1,4,8]$
for i:1 step 1 thru length(y) do
( tt[i]: %solve( [(x[i]^2-y[i])<0, (x[i])<0], [x[i]]),
display (tt[i])
);
the answer:
(%o144) [1,4,8]
tt[1]=%union([-1<x[1],x[1]<0])
tt[2]=%union([-2<x[2],x[2]<0])
tt[3]=%union([x[3]<0,-(x[3]^2-8)>0])
(%o145)
I would like to know :
1) how to get a result of tt[3] like that:
%union( [x[3]<0 , x[3]>-2.828])
and:
2) how to display the results of "x" without using "display (tt[i])".
For example when I use the single variable (without list and "for") like this:
y : 8$
%solve( [(x^2-y)<0, (x)<0], [x]);
I get the following result of x:
(%o157) %union([x<0,-(x^2-8)>0])
I will be thankfur for help,
Best Regards
Sarah