Vickram,
Thanks for your interest in Maxima.
What problem are you trying to solve? i.e. why do you want to calculate a
numeric integral to 200 digits of precision in the first place?
Also, what do you mean by "Maxima cannot compute up to 1e+13!"? Maxima
floating-point numbers have standard IEEE float ranges (up to roughly
1e+308). Maxima bfloat's have essentially unlimited range (10^10^100b0 is
unproblematic).
Perhaps if you could show us a self-contained minimal example of how to
generate the error you're seeing, we could help find the problem.
-s
--
On Fri, Dec 7, 2012 at 12:07 AM, Vickram Ratnam <accts at goldox.mu> wrote:
> Hi,****
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> I?m new to Maxima. I am using Maxima for windows!****
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> I?m trying to compute a definite integral using Woollett?s tanh-sinh
> maxima code and the maxima built-in integration methods but with no success!
> ****
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> My function is the following:****
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> 1/sqrt((.0000812*(1+x)^4)+(.2719188*(1+x)^3)+(0*(1+x)^2)+.728)****
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> From 0 to 1e+13****
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> Using preferably tanh-sinh quadrature and to over 300 digits accuracy!****
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> I can do the same with python mpmath and on mathematica. I wanted to check
> the answers from a third source.****
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> But Maxima cannot compute up to 1e+13!****
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> Can I do that or is Maxima limited to certain accuracy?****
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> Thanks****
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> Vick****
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