A function from some subset of C to C (complex numbers) is analytic on an open set S if the function is differentiable on S.
A function from some subset of R to R (real numbers) is analytic on an open set S if the
--Barton
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From: maxima-bounces at math.utexas.edu [maxima-bounces at math.utexas.edu] on behalf of Dennis Darland [dennis.darland at yahoo.com]
Sent: Monday, February 04, 2013 16:14
To: math maxima
Subject: "Begs the question"
The meaning of expressions can change with time. As in "begs the question." Misuse of an expression can change its meaning. For me it is "begging the question" (in the new sense) whether I am using the term "analytic" solution in my test results correctly. I have checked a couple dictionaries of mathematics with no luck. I know "analytic" does have another meaning, but I am not sure if I am using it wrong. Also I am really speaking of a numerical evaluation of that analytic solution. (Or should I be saying "closed form" solution?) I have been working on all this practically by myself, on and off, for over thirty years, with no one to ask questions of, or talk to. I am not intending to misuse "analytic".
Dennis J. Darland
dennis.darland at yahoo.com
http://dennisdarland.com/http://dennisdarland.com/dennisdaze/http://dennisdarland.com/philosophy/http://sode.sourceforge.net/
?Why is it not possible to get some of the people in these downtrodden countries to like us instead of hating us?", Eisenhower (From _Beyond America's Grasp: A Century of Failed Diplomacy in the Middle East_ by Stephen P. Cohen, page 67)
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